Newton's Law of Cooling
Newton's law of cooling describes the cooling rate of a body relative to the temperatures of the object and the surroundings. The following data was collected for a container of water at an initial temperature of 100°C placed inside a freezer compartment at 0°C. The time is measured in minutes and the temperature is measured in degrees Celsius.
|
Time |
Temp |
Time |
Temp |
Time |
Temp |
| 0 | 100 | 40 | 67 | 80 | 45 |
| 2 | 98 | 42 | 66 | 82 | 44 |
| 4 | 96 | 44 | 64 | 84 | 43 |
| 6 | 94.5 | 46 | 63 | 86 | 42 |
| 8 | 92.5 | 48 | 62 | 88 | 41.5 |
| 10 | 90.5 | 50 | 61 | 90 | 40.5 |
| 12 | 88 | 52 | 59 | 92 | 40 |
| 14 | 87 | 54 | 58 | 94 | 39 |
| 16 | 85 | 56 | 57 | 96 | 38.5 |
| 18 | 93.5 | 58 | 56 | 98 | 37.5 |
| 20 | 82 | 60 | 55 | 100 | 36.5 |
| 22 | 80 | 62 | 53.5 | 102 | 36 |
| 24 | 78.5 | 64 | 53 | 104 | 35.5 |
| 26 | 77 | 66 | 52 | 106 | 34.5 |
| 28 | 75 | 68 | 50.5 | 108 | 34 |
| 30 | 74 | 70 | 49.5 | 110 | 33 |
| 32 | 73 | 72 | 48.5 | 112 | 32.5 |
| 34 | 71 | 74 | 47.5 | 114 | 32 |
Newton's Law of Cooling
Using a statistical package or a graphing calculator, make a scatterplot with time as the independent variable and temperature as the dependent variable. With a statistical package or a graphing calculator fit a quadratic equation to this data. Use this equation to predict the water temperature after 2 hours, 3 hours, and 4 hours.
With a statistical package or a graphing calculator fit an equation of the form ln y = . . . . Rewrite this equation using properties of exponents so it is of the form y = . . . . Use this equation to predict the water temperature after 2 hours, 3 hours, and 4 hours.
Compare your quadratic predictions with your exponential predictions. Which equation do you think gives the better prediction, the quadratic or exponential? Explain.